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# Answers to Einstein I.Q. Test

The test is on this page. In defense of puzzles 4 & 9, I did warn you that two of the puzzles contained trick questions. If you get a chance, also see problems 1-15 in the book Brain Bafflers, especially problem #5. I figure that if a big name publisher like Sterling Publishing Co., Inc. is willing to produce puzzles like these, I can too! If you don't like the trick questions, don't be dismayed. Very few of my quizzes use them.

1. 132. Think of it this way: the first person shakes hands with 11 people, the second person also shakes hands with 11 people, but you only count 10, because the hand shake with the first person was already counted. Then add 9 for the third person, 8 for the fourth, & so on. 66 hand shakes took place before & after the meeting, for a total of 132.

2. 19%. This puzzle was easy. Divide the number of juniors (187) by the total number of students (981), & then multiply the number by 100 to convert to a percentage.

3. 9. To verify this, you can make a drawing of a cube, & number each of its 12 edges. Then, always starting from 1 corner & 1 edge, you can determine all of the possible paths for tracing along the edges of a cube. There is no need to start from other corners or edges of the cube, as you will only be repeating the same paths. The process is a little more involved than this, but is useful for solving many types of spatial puzzles.

4. 44. 36 of the cubes have EXACTLY 2 of their sides painted black, but because a cube with 3 of its sides painted black has 2 of its sides painted black, you must also include the corner cubes. This was a trick question, but hopefully the title of the puzzle tipped you off to this.

5. Eating hurts my tooth.

6. 10000. Again, the title holds a hint, although this is still a tough puzzle. The series begins with the number 1, & continues through 22, giving a 1 for each prime number, & a 0 for each number that is not prime. Of the last 5 numbers (23-27), only 23 is prime.

7. \$333,062,500. To begin with, you want to know the total number of days: 365 x 50 = 18250. By experimentation, the following formula can be discovered, & used to determine the amount earned for any particular day: 1 + 2(x-1), with x being the number of the day. The title again holds a hint, although this 1 may have been a bit more obscure. Take half of the 18250 days, & pair them up with the other half in the following way: day 1 with day 18250, day 2 with day 18249, & so on, & you will see that if you add these pairs together, they always equal \$36500. Multiply this number by the total number of pairs (9125), & you have the amount you would have earned in 50 years. Except for math gurus (I'm not 1), this puzzle may have proved to be tough. Someone pointed out that a much easier method for solving this problem is squaring the total number of days worked - I like doing things the hard way, though.

8. \$22176.

9. All of them. Another trick question!

10. The title refers to the number & type of pieces on a chess board: 2 kings, 2 queens, 16 pawns, 4 rooks, 4 bishops, & 4 knights, so the answer is k or n (the latter due to chess notation - k is already taken for the king).

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